This vignette demonstrates how get started with using the epichains package for simulating transmission chains or estimating the likelihood of observing a transmission chain.
vignette("theoretical_background")
.vignette("design-principles")
.Infectious disease epidemics spread through populations when a chain of infected individuals transmit the infection to others. Branching processes can be used to model this process. A branching process is a stochastic process where each infectious individual in a generation gives rise to a random number of individuals in the next generation, starting with the index case in generation 1. The distribution of the number of offspring is called the offspring distribution.
The size of the transmission chain is the total number of individuals infected by a single case, and the length of the transmission chain is the number of generations from the first case to the last case they produced before the chain ended. The size calculation includes the first case and the length calculation includes the first generation when the first case starts the chain (See figure below).
epichains provides methods to analyse and simulate the size and length of branching processes with an arbitrary offspring distribution. These can be used, for example, to analyse the distribution of chain sizes or length of infectious disease outbreaks, as discussed in Farrington, Kanaan, and Gay (2003) and Blumberg and Lloyd-Smith (2013).
Suppose we have observed a number of transmission chains, each arising from a separate index case. What are the likely transmission properties (reproduction number and/or superspreading coefficient) that generated these chains (assuming these parameters are the same across all the chains)?
The first step in answering this question is to calculate the
likelihood of observing the observed chain summaries given the
transmission properties. This is where the likelihood()
function comes in. The returned estimate can then be used to infer the
transmission properties using estimation frameworks such as maximum
likelihood or Bayesian inference.
epichains does not provide these estimation frameworks.
likelihood()
This function calculates the likelihood/loglikelihood of observing a vector of outbreak summaries obtained from transmission chains. “Outbreak summaries” here refer to transmission chain sizes or lengths/durations.
likelihood()
requires a vector of chain summaries (sizes
or lengths), chains
, the corresponding statistic to use,
statistic
, the offspring distribution,
offspring_dist
and its associated parameters.
offspring_dist
is specified by the R function that is
used to generate random numbers, i.e. rpois
for Poisson,
rnbinom
for negative binomial, or a custom function.
By default, the result is a log-likelihood but if
log = FALSE
, then likelihoods are returned (See
?likelihood
for more details).
To understand how likelihood()
works see the section on
How likelihood()
works.
Let’s look at the following example where we estimate the
log-likelihood of observing chain_sizes
.
set.seed(121)
# example of observed chain sizes
# randomly generate 20 chains of size between 1 to 10
chain_sizes <- sample(1:10, 20, replace = TRUE)
chain_sizes
#> [1] 4 7 4 9 1 3 7 5 1 8 10 2 1 2 4 5 10 6 8 7
# estimate loglikelihood of the observed chain sizes for given lambda
likelihood_eg <- likelihood(
chains = chain_sizes,
statistic = "size",
offspring_dist = rpois,
nsim_obs = 100,
lambda = 0.5
)
# Print the estimate
likelihood_eg
#> [1] -67.82879
likelihood()
, by default, returns the joint
log-likelihood, given by the sum of log-likelihoods of each observed
chain. If instead the individual log-likelihoods are desired (for
example for calculating Watanabe–Akaike
information criterion values, then the individual
argument must be set to TRUE
. To return likelihoods
instead, set log = FALSE
.
set.seed(121)
# example of observed chain sizes
# randomly generate 20 chains of size between 1 to 10
chain_sizes <- sample(1:10, 20, replace = TRUE)
chain_sizes
#> [1] 4 7 4 9 1 3 7 5 1 8 10 2 1 2 4 5 10 6 8 7
# estimate loglikelihood of the observed chain sizes
likelihood_ind_eg <- likelihood(
chains = chain_sizes,
statistic = "size",
offspring_dist = rpois,
nsim_obs = 100,
lambda = 0.5,
individual = TRUE
)
# Print the estimate
likelihood_ind_eg
#> [[1]]
#> [1] -3.098612 -4.508584 -3.098612 -5.269208 -0.500000 -2.480829 -4.508584
#> [8] -3.622329 -0.500000 -4.900542 -5.619471 -1.693147 -0.500000 -1.693147
#> [15] -3.098612 -3.622329 -5.619471 -4.086190 -4.900542 -4.508584
likelihood()
uses the argument obs_prob
to
model the observation probability.
By default, it assumes perfect observation, where
obs_prob = 1
(See ?likelihood
), meaning that
all transmission events are observed and recorded in the data.
If observations are imperfect, the obs_prob
must be less
than 1. In the case of imperfect observation, “true” chain sizes or
lengths are simulated nsim_obs
times, and the likelihood
calculated for each of the simulations.
For example, if the probability of observing each case is
obs_prob = 0.30
, we use
set.seed(121)
# example of observed chain sizes; randomly generate 20 chains of size 1 to 10
chain_sizes <- sample(1:10, 20, replace = TRUE)
# get their likelihood
liks <- likelihood(
chains = chain_sizes,
statistic = "size",
offspring_dist = rpois,
obs_prob = 0.3,
lambda = 0.5,
nsim_obs = 10
)
liks
#> [1] -183.8670 -162.1382 -166.6720 -170.1077 -152.9557 -157.9814 -166.0587
#> [8] -174.8488 -156.4197 -160.0229
This returns 10
likelihood values (because
nsim_obs = 10
), which can be averaged to come up with an
overall likelihood estimate.
likelihood()
workslikelihood()
first checks if an analytical solution of
the likelihood exists for the given offspring distribution and chain
statistic specified. If there’s none, simulations are used to estimate
the likelihoods.
The epichains package includes closed-form (analytical) solutions for calculating the likelihoods associated with certain summaries of transmission chains (“size” or “length”) for specific offspring distributions.
For the size distributions, the package provides the Poisson, negative binomial, and gamma-borel mixture.
To provide the gamma-Borel size likelihood, the Borel distribution is needed. However, base R does not provide this distribution natively like poisson and gamma, so epichains provides its density and random generator.
For the length distribution, there’s the Poisson and geometric
distributions. These can be used with likelihood()
based on
what is specified for offspring_dist
and
statistic
.
If an analytical solution does not exist, an internal simulation
function, .offspring_ll()
is employed. It uses simulations
to approximate the probability distributions (using
a linear approximation to the cumulative distribution for unobserved
sizes/lengths). If simulation is to be used, an extra argument
nsim_offspring
must be passed to likelihood()
to specify the number of simulations to be used for this approximation.
Approximate values of the likelihood will vary with every call to the
simulation (because the simulations used for estimation vary), and it
may be worth calling likelihood()
multiple times in this
case to see the error this may introduce.
For example, let’s look at an example where chain_sizes
is observed and we want to calculate the likelihood of this being drawn
from a binomial distribution with probability
prob = 0.9
.
set.seed(121)
# example of observed chain sizes; randomly generate 20 chains of size 1 to 10
chain_sizes <- sample(1:10, 20, replace = TRUE)
# get their likelihood
liks <- likelihood(
chains = chain_sizes,
offspring_dist = rbinom,
statistic = "size",
size = 1,
prob = 0.9,
nsim_offspring = 250
)
liks
#> [1] -56.76805
We want to simulate a scenario where a number of chains are each produced by a separate index case. We want to simulate the chains of transmission that result from these cases, given a specific offspring distribution and a reproduction number.
There are two simulation functions, herein referred to collectively
as the simulate_*()
functions that can help us achieve
this.
simulate_chains()
simulate_chains()
simulates an outbreak from a given
number of infections and an offspring distribution. By default, it
assumes the population is infinite with no pre-existing immunity.
The function tracks and returns information on infectors (ancestors), infectees, the generation of infection, and the time, if a generation time function is specified.
Let’s look at an example where we simulate a transmission tree for 10 index cases. We assume a poisson offspring distribution with mean, lambda = 0.9, and a generation time of 3 days:
set.seed(32)
# Define generation time
generation_time_fn <- function(n) {
gt <- rep(3, n)
return(gt)
}
sim_chains <- simulate_chains(
n_chains = 10,
statistic = "size",
offspring_dist = rpois,
stat_threshold = 10,
generation_time = generation_time_fn,
lambda = 0.9
)
head(sim_chains)
#> chain infector infectee generation time
#> 11 1 1 2 2 3
#> 12 2 1 2 2 3
#> 13 3 1 2 2 3
#> 14 3 1 3 2 3
#> 15 4 1 2 2 3
#> 16 6 1 2 2 3
By default, simulate_chains()
assumes an infinite
population but can account for susceptible depletion when a finite
pop
is specified.
Pre-existing immunity levels can also be specified, which will be
applied to pop
before the simulation is initialised.
Here is a quick example where we simulate an outbreak in a population of size 1000 with 10 index cases and 10/ pre-existing immunity. We assume individuals have a poisson offspring distribution with mean, lambda = 1, and fixed generation time of 3:
set.seed(32)
# Define generation time
generation_time_fn <- function(n) {
gt <- rep(3, n)
return(gt)
}
sim_chains_with_pop <- simulate_chains(
pop = 1000,
n_chains = 10,
percent_immune = 0.1,
offspring_dist = rpois,
statistic = "size",
lambda = 1,
generation_time = generation_time_fn
)
head(sim_chains_with_pop)
#> chain infector infectee generation time
#> 11 1 1 2 2 3
#> 12 2 1 2 2 3
#> 13 3 1 2 2 3
#> 14 3 1 3 2 3
#> 15 4 1 2 2 3
#> 16 6 1 2 2 3
simulate_chain_stats()
simulate_chain_stats()
is a performant version of
simulate_chains()
that does not track information on each
infector and infectee. It returns the eventual size or length/duration
of each transmission chain. This function is especially useful for
calculating numerical likelihoods in likelihood()
.
Here is an example to simulate the previous examples without intervention, returning the size of each of the 10 chains. It assumes a Poisson offspring distribution distribution with mean of 0.9.
set.seed(123)
simulate_chain_stats_eg <- simulate_chain_stats(
n_chains = 10,
statistic = "size",
offspring_dist = rpois,
stat_threshold = 10,
lambda = 0.9
)
# Print the results
simulate_chain_stats_eg
#> `epichains_summary` object
#>
#> [1] 1 Inf 4 4 Inf 1 2 Inf 5 3
#>
#> Simulated sizes:
#>
#> Max: >=10
#> Min: 1
You can run summary()
on the object returned by
simulate_chains()
to obtain the chain summaries per index
case.
set.seed(32)
# Define generation time
generation_time_fn <- function(n) {
gt <- rep(3, n)
return(gt)
}
sim_chains <- simulate_chains(
n_chains = 10,
statistic = "size",
offspring_dist = rpois,
stat_threshold = 10,
generation_time = generation_time_fn,
lambda = 0.9
)
summary(sim_chains)
#> `epichains_summary` object
#>
#> [1] Inf 2 Inf 2 1 Inf 3 Inf 9 1
#>
#> Simulated sizes:
#>
#> Max: >=10
#> Min: 1
# Example with simulate_chain_stats()
set.seed(32)
simulate_chain_stats_eg <- simulate_chain_stats(
n_chains = 10,
statistic = "size",
offspring_dist = rpois,
stat_threshold = 10,
lambda = 0.9
)
# Get summaries
summary(simulate_chain_stats_eg)
#> $n_chains
#> [1] 10
#>
#> $max_stat
#> [1] Inf
#>
#> $min_stat
#> [1] 1
This summary is the same as the output of
simulate_chain_stats()
if the same inputs are used.
simulate_chain_stats()
is a more performant version of
simulate_chains()
, hence, you can use it instead, if you
are only interested in the summary of the simulated chains without
details about the infection tree. :::
We can confirm if the two outputs are the same using
base::setequal()
, which checks if two objects are equal and
returns TRUE/FALSE
.
You can aggregate <epichains_tree>
objects
returned by simulate_chains()
a
<data.frame>
with columns “cases” and either
“generation” or “time”, depending on the value of by
.
To aggregate over “time”, you must have specified a generation time
distribution (generation_time
) in the simulation step.
# Example with simulate_chains()
set.seed(32)
# Define generation time
generation_time_fn <- function(n) {
gt <- rep(3, n)
return(gt)
}
sim_chains <- simulate_chains(
n_chains = 10,
statistic = "size",
offspring_dist = rpois,
stat_threshold = 10,
generation_time = generation_time_fn,
lambda = 0.9
)
aggregate(sim_chains, by = "time")
#> time cases
#> 1 0 10
#> 2 3 12
#> 3 6 14
#> 4 9 17
#> 5 12 3
#> 6 15 4
#> 7 18 3
We can plot individual chains in an <epichains>
object using the {epicontacts}
package.
To do this, we first need to create an
<epicontacts>
object using the
epicontacts::make_epicontacts()
function, which requires a
linelist and a contacts data.frame (See
?epicontacts::make_epicontacts()
).
<epicontacts>
and <epichains>
objectsFor the epicontacts::make_epicontacts()
function to
work:
linelist
and contacts
data.frames must
have a column named “id” that uniquely identifies each case.linelist
and contacts
objects can be
the same.An <epichains>
object contains multiple
independent chains with their own unique infectee ids, so this does not
work out of the box with make_epicontacts()
unless you use
a subset chain.
For now, we will have to select and visualise individual chains
from the <epichains>
object.
In future versions of this package, we will make this interaction
seamless by providing user-friendly functionality to convert an
<epichains>
object to an
<epicontacts>
in a way that allows us to plot all
chains at once.
Let’s subset one of the chains with the biggest size from the
sim_chains
object created above.
# Get the biggest chain
longest_chain <- sim_chains[sim_chains$chain == which.max(
unname(table(sim_chains$chain))
), ]
# Convert to data.frame to view the whole data
as.data.frame(longest_chain)
#> chain infector infectee generation time
#> 6 6 NA 1 1 0
#> 16 6 1 2 2 3
#> 17 6 1 3 2 3
#> 18 6 1 4 2 3
#> 27 6 2 5 3 6
#> 28 6 3 6 3 6
#> 29 6 3 7 3 6
#> 30 6 4 8 3 6
#> 42 6 5 9 4 9
#> 43 6 6 10 4 9
#> 44 6 7 11 4 9
#> 45 6 8 12 4 9
Now, we can plot the chain using the {epicontacts}
package.
# Create an `<epicontacts>` object
epc <- make_epicontacts(
linelist = longest_chain,
contacts = longest_chain,
id = "infectee",
from = "infector",
to = "infectee",
directed = TRUE
)
# Plot the chain
plot(epc)
Aggregated <epichains_tree>
objects can also be
plotted using base R or ggplot2
with little to no data
manipulation.
Here is an end-to-end example from simulation through aggregation to plotting.
# Run simulation with simulate_chains()
set.seed(32)
# Define generation time
generation_time_fn <- function(n) {
gt <- rep(3, n)
return(gt)
}
sim_chains <- simulate_chains(
n_chains = 10,
statistic = "size",
offspring_dist = rpois,
stat_threshold = 1000,
generation_time = generation_time_fn,
lambda = 2
)
# Aggregate cases over time
sim_chains_aggreg <- aggregate(sim_chains, by = "time")
# Plot cases over time
plot(
sim_chains_aggreg,
type = "b",
col = "red",
lwd = 2,
xlab = "Time",
ylab = "Cases"
)